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Whole number arithmetic

SECTION 1-WHOLE NUMBER ARITHMETIC





DIVISION-Part 2

Division with a divisor larger than 10 may look scarier than the divsion problems that you were just exposed to, but you are going to follow the same exact steps as before. So don't panic when I ask you to divide 79,800 by 25, or if I ask you to divie 87,535 by 287.

With this in mind, let the examples begin. There will be a total of 4 examples.

Division example 1

79,800 ¸ 25 The dividend is 79,800 and the divisor is 25

First write down the problem as shown.
We will start with the 7 in 79,800. Can 25 go into 7?
No
We go on to the next digit (9), and ask can 25 go into 79?
Yes
What is the maximum number of times that 25 go into 79, without going over? (Isn't this fun, just like playing "The Price is Right.")

For our first guess let's try 2.
2 x 25 = 50, and 79 - 50 = 29. Now this difference is actually larger than our divisor (25). That tells us that we can get closer to 79 than this guess. Our guess of 2 was too small.
Okay let's try four.
25 x 4 = 100. The number 100 is greater than 79. Our guess of 4 was too big.
Okay let's that leaves us with three.
25 x 3 = 75, and 79 - 75 = 4. Notice that when we completed the subtraction the result was actually less than our divisor (25). that tells us that this is the right guess.

Write the 3 in the area reserved for the quotient, and place it directly above the 9 that appears in 79,800.

Multiply this three by our divisor getting a product of 75. Place the 75 directly below the 79 that we just investigated. Now subtract the 75 from the 79 getting a remainder of 4.
The next digit in 79800 is 8. Place this 8 on the right hand side of our remainder thereby changing the 4 into 48.

Can 25 go into 48?
Yes
What is the maximum number of times that 25 go into 48, without going over?

Let's try two.
2 x 25 = 50, which is larger than 48. Our guess of 2 was too big.
Okay let's that leaves us with one.
25 x 1 = 25, and 48 - 25 - 23. Notice that when we completed the subtraction the result was actually less than our divisor (25). That tells us that this is the right guess.

Write the 1 in the area reserved for the quotient, and place it directly above the 8 in 79800.

Multiply this 1 by the divisor getting 25. Write this 25 directly below the 48 that we just investigated. Now subtract the 25 from the 48 getting a remainder of 23.
The next digit in 79800 is 0. Place this zero on the right hand side of our remainder thereby changing the 23 into 230.
How many times does 25 go into 230? Well let's see.

Let's try 7.
25 x 7 = 175 and 230 - 175 = 55. That difference is larger than our divisor. That indicates that will can get closer to 230 than 175. Our guess of 7 was too small.
Let's try 8.
25 x 8 = 200 and 230 - 200 = 30. That difference is larger than our divisor. That indicates that will can get closer to 230 than 200. Our guess of 8 was too small.
Let's try 9.
25 x 9 = 225 and 230 - 225 = 5. That difference is less than our divisor. That indicates that this is the correct guess.

Write the 9 in the area reserved for the quotient, and place it directly above the first zero in 79800.

Multiply this 9 by the divisor getting a product of 225. Write the 225 directly below the 230 that we just investigated. Now subtract 225 from 230 getting a remainder of 5.
The next digit in 79800 is 0. Place this zero on the right hand side of our remainder thereby changing the 5 into 50.
How many times does 25 go into 50? Well let's see.

Let's try 2.
25 x 2 = 50. We couldn't possiblt get any closer to 50 than that.

Write the 2 in the area reserved for the quotient and place it directly above the second zero in 79800. Multiply this two by the divisor getting a product of 50. Write this 50 directly below the 50 that we just investigated. Subtract 50 from 50 gettinga remainder of 0.

There are no more digits in the dividend. Therefore we are finished.
79,800 ¸ 25 = 3,192
To understand what this solution means consider the following facts.
The division problem "79,800 ¸ 25" is basically asking us "how many groups of 25 are required to reach a grand total of 79,800?" The quotient of 3,192 is telling us that "3,192 groups of 25 are necessary to reach a grand total of 79,800." Therefore if we wanted to check our answer we should multiply 3,192 and 25. The resulting product should be 79,800.
Assignment: verify that "3,192 x 25 = 79,800."

*****


Division example 2

1,885 ¸ 145
Don't panic at the sight of this hideous problem. Just take it one step at a time.
The dividend is 1,885 and the divisor is 145

First write down the problem as shown.
We will start with the 1 in 1,885. Can 145 go into 1?
No
We go on to the next digit (8), and ask can 145 go into 18?
No
We go on to the next digit (8), and ask can 145 go into 188?
Yes
What is the maximum number of times that 145 go into 188, without going over?

Let's try one.
145 x 1 = 145, and 188 - 145 = 43. Notice that when we completed the subtraction the result was actually less than our divisor (145). that tells us that this is the right guess.

Write the 1 in the area reserved for the quotient, and place it directly above the second 8 in 1885.

Multiply this 1 by the divisor getting a product of 145. Place this 145 below the 188 that we just investigated. Subtract the 145 from the 188 getting a remainder of 43.
The next digit in 1885 is 5. Place this 5 on the right hand side of our remainder thereby transforming 43 into 435.

Can 25 go into 48?
Yes
What is the maximum number of times that 145 can go into 435.

Let's try two. 2 x 145 = 290 and 435 - 290 = 145. This difference is actually equal to our divisor. That indicates that we can get closer to 435 than 290. Our guess of 2 was too small.
Let's try three. 3 x 145 = 435. We couldn't possibly get any closer to 435 than that.

Write the 3 in the area reserved for the quotient, and place it directly above the 5 in 1885.

Multiply this 5 by the divisor getting a product of 435. Write this product directly below the 435 that we just investigated. Subtract the two numbers gettinga remainder of 0.

There are no more digits in the dividend. Therefore we are finished.
1,885 / 145 = 13
To understand what this solution means consider the following facts.
The division problem "1,885 / 145 " is basically asking us "how many groups of 145 are required to reach a grand total of 1,885?" The quotient of 13 is telling us that "13 groups of 145 are necessary to reach a grand total of 1,885." Therefore if we wanted to check our answer we should multiply 13 and 145. The resulting product should be 1,885.
Assignment: verify that "13 x 145 = 1,885."

*****


Division example 3

87,535 ¸ 287
The dividend is 87535 and the divisor is 287

First write down the problem as shown.
The divisor 287 cannot go into 8.
The divisor 287 cannot go into 87.
However the divisor 287 can go into 875. In fact it goes into 287 a maximum of 3 times, and it leaves a remainder of 14.
Assignment: confirm that 287 divides 875 a maximum of 3 times with a remainder of 14.
Note: Stating that "287 divides 875 a maximum of 3 times" is just another way of writing "287 goes into 874 a maximum of 3 times."

This is illustrated for you in the diagram to the left. Notice the placement of the numbers.
Bring down the next digit in 87535 and place it on the right hand side of our remainder. After this task is completed, the 14 is changed into 143.
Now 287 cannot go into 143 so place a 0 in the area reserved for the quotient, and place it above the 3 in 87535
Bring down the next digit in 87535 and place it on the right hand side of the "143." After this task is completed, the 143 is changed into 1435.
How many times does 287 go into 1435? Well let's see.

Let's try 4.
4 x 287 = 1148 and 1435 - 1148 = 287. That difference is actually equal to our divisor. That indicates that will can get closer to 1435 than 1148. Our guess of 4 was too small.
Let's try 6.
6 x 287 = 1722, which is actually larger than 1435. That tells us that our guess of 6 was too large.
That leaves us with 5.
5 x 287 = 1435. We couldn't possibly get any closer to 1435 than that!

Write a 5 directly in the area reserved for the quotient, and place it above the 5 in 87535.

Multiply this 5 by our divisor getting a product of 1435. Write this product below the 1435 we just investigated. Subtract the two numbers getting a remainder of 0.

There are no more digits in the divident. Therefore we are finished.
87,535 ¸ 287 = 305
To understand what this solution means consider the following facts.
The division problem "87,535 ¸ 287" is basically asking us "how many groups of 287 are required to reach a grand total of 87,535?" The quotient of 305 is telling us that "305 groups of 287 are necessary to reach a grand total of 87,535." Therefore if we wanted to check our answer we should multiply 305 and 287. The resulting product should be 87,535.
Assignment: verify that "305 x 287 = 87.535."

*****


Division example 4

330,225 ¸ 110
The dividend is 330,225 and the divisor is 110

First write down the problem as shown.
The divisor 110 cannot go into 3 (i.e. it cannot divide 3).
The divisor 110 cannot go into 33 (i.e. it cannot divide 33).
The divisor 110 can divide 330 (i.e. it can go into 330). In fact 110 divides 330 a maximum of 3 times leaving a remainder of 0. Assignment: Confirm this for yourself.

This activity is illustrated for you in the diagram to the left. Notice the placement of the numbers.
Bring down the next digit in 330225. This will make the "0" into "02." Now we all know that "02" is equal to 2, but we will keep the zero around just to make sure everything is nice and neat. Zero is a place holder.
Now 110 cannot go into 2 so place a 0 in the space reserved for the quotient, and place it above the first two in 330225
Bring down the next digit in 330225. This will make the "02" into "022." Now we all know that 022 is equal to 22, but we will keep the zero around simply so everything will stay nice and neat. Here zero is a place holder.
Now 110 cannot divide 22 so place a 0 in the space reserved for the quotient, and place it above the second two in 330225
Bring down the next digit in 330225. This will change "022" into "0225."
How many times does 110 go into 225? Well let's see.

Let's try 2.
2 x 110 = 220 and 225 - 220 = 5. That difference is actually less than our divisor. That indicates that this is the correct guess.

Write a 2 in the space reserved for the quotient, and place it above the 5 in 330225.

Multiply this 2 by the divisor getting a product of 220. Write this product directly below the 225 that we just investigated. We will then subtract the 220 from the 225 getting a remainder of 5.

There are no more digits in the dividend. Therefore we are finished.
330,225 ¸ 110 = 3,002r5 (3,002 witha remainder of 5)
To understand what this solution means consider the following facts.
The division problem "330,225 ¸ 110" is basically saying that we have a group of 110 objects. It is asking us "how many of these groups are required to reach a grand total of 330,225 objects?" The quotient of 3002r5 is telling us that "3002 groups of 110 are necessary to get near 330,225, and then you have to add 5 more objects to this product." In other words if we multiplied 3002 by 110, and then added 5 to this product we would reach 330,225.
3002 x 110 = 330,220 and 330,220 + 5 = 220,225.



Ready to try your hands on division?
You better be, cause here goes!

Click on the "generate a division problem" button to see your exercise. Place your answer in the text box and then click the "check my answer" button. The computer will then tell you whether or not your answer is correct.

After you complete the problem, you can generate another problem by first clicking the "reset button" and then clicking the "generate a division problem" button. Continue as many times as you wish, and then:





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All text, images, and source code c2003 Martin Selditch.